C++: typeid

Yao Yao on April 24, 2015
  • Published in category
  • C++

整理自:Thinking in C++, Volume 2

typeid operator returns an object of class type_info, which yields information about the type of object to which it was applied. If the type is polymorphic, it gives information about the most derived type that applies (the dynamic type); otherwise it yields static type information.

#include <iostream>
#include <typeinfo>
using namespace std;

struct PolyBase {
    virtual ~PolyBase() {}

struct PolyExt : PolyBase {
    PolyExt() {}

struct NonPolyBase {};

struct NonPolyExt : NonPolyBase {
    NonPolyExt(int) {}

int main() {
	// Test polymorphic Types
    const PolyExt polyExt;
    const PolyBase* pPolyBase = &polyExt;
	cout << typeid(pPolyBase).name() << endl;
    cout << typeid(*pPolyBase).name() << endl;
    cout << boolalpha << (typeid(*pPolyBase) == typeid(polyExt))
         << endl;
    cout << (typeid(PolyExt) == typeid(const PolyExt))
         << endl;
	// Test non-polymorphic Types
    const NonPolyExt nonPolyExt(1);
    const NonPolyBase* pNonPolyBase = &nonPolyExt;
	cout << typeid(pNonPolyBase).name() << endl;
    cout << typeid(*pNonPolyBase).name() << endl;
    cout << (typeid(*pNonPolyBase) == typeid(nonPolyExt)) << endl;
	// Test a built-in type
    int i;
	cout << typeid(i).name() << endl;

// output:
	struct PolyBase const *
	struct PolyExt
	struct NonPolyBase const *
	struct NonPolyBase
  • Notice that RTTI ignores top-level const and volatile qualifiers.
  • It turns out that you can’t store the result of a typeid operation in a type_info object, because there are no accessible constructors and assignment is disallowed. You must use it as we have shown.
  • In addition, the actual string returned by type_info::name() is compiler dependent.
  • Applying typeid to an expression that dereferences a null pointer will cause a bad_typeid exception (also defined in <typeinfo>).
  • You can also apply typeid to nested class.
  • You can also ask a type_info object if it precedes another type_info object in the implementation-defined “collation sequence”.
    • if(typeid(foo).before(typeid(bar)))
    • This is useful if you use type_info objects as keys.

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